Ask your own question, for FREE!
Mathematics 28 Online
OpenStudy (anonymous):

Find the exact solutions to each equation for the interval 0<=x<2pi. sin 2x=-sqrt2 cos x

myininaya (myininaya):

sin2x=2sinxcosx 2sinxcosx=-sqrt{2}cosx 2sinxcosx+sqrt{2}cosx=0 cosx(2sinx+sqrt{2}=0 cosx=0 => x=pi/2, 3pi/2 2sinx+sqrt{2}=0 2sinx=-sqrt{2} sinx=-sqrt{2}/2 =>x=5pi/4, 7pi/4

myininaya (myininaya):

remember sin2x=2sinxcosx sin(x+x)=sinxcosx+sinxcosx sin(2x)=2sinxcosx

OpenStudy (anonymous):

thanks again, i have one more problem left :D

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Latest Questions
NaiNoah: should it hurt when i move/flex my thigh?
2 hours ago 7 Replies 3 Medals
Gucchi: english help.
12 hours ago 8 Replies 1 Medal
Gucchi: .. english help
13 hours ago 5 Replies 1 Medal
Gucchi: english help
14 hours ago 10 Replies 2 Medals
Gucchi: english HELP
14 hours ago 10 Replies 2 Medals
Gucchi: ````````````` english help
15 hours ago 7 Replies 1 Medal
Gucchi: english help `
18 hours ago 11 Replies 1 Medal
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!