Ask your own question, for FREE!
Mathematics
OpenStudy (anonymous):

Find the exact solutions to each equation for the interval 0<=x<2pi. sin 2x=-sqrt2 cos x

myininaya (myininaya):

sin2x=2sinxcosx 2sinxcosx=-sqrt{2}cosx 2sinxcosx+sqrt{2}cosx=0 cosx(2sinx+sqrt{2}=0 cosx=0 => x=pi/2, 3pi/2 2sinx+sqrt{2}=0 2sinx=-sqrt{2} sinx=-sqrt{2}/2 =>x=5pi/4, 7pi/4

myininaya (myininaya):

remember sin2x=2sinxcosx sin(x+x)=sinxcosx+sinxcosx sin(2x)=2sinxcosx

OpenStudy (anonymous):

thanks again, i have one more problem left :D

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Latest Questions
Mathplayer223: chemistry
40 minutes ago 2 Replies 0 Medals
Trickjoker: I HAVE FOUND OUT THE ASHWIN THING!!!
29 minutes ago 20 Replies 1 Medal
Foreverangel: Find RT 10 m 13m 14 m 16 m
19 minutes ago 10 Replies 1 Medal
Trickjoker: Which mod on QC is named ashwin?
39 minutes ago 54 Replies 0 Medals
Mathplayer223: chemistry
52 minutes ago 4 Replies 0 Medals
Mathplayer223: chemistry
1 hour ago 2 Replies 0 Medals
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!