Question

find d^2*y/dx^2 in terms of x and y for 1-xy=x-y?plzz:)..dont rlly understand what its asking:(

Answer 1

this is asking for hte second derivative. So take the derivative of the derivative.

Answer 2

\[d ^{2}y/dx ^{2}\]

Answer 3

so first solve for y in terms of x.

Answer 4

thts wat it says on the paper

Answer 5

hm.

Answer 6

are you sure:\[1-xy=x-y\] is the equation?

Answer 7

yes

Answer 8

Implicit differentiation!

Answer 9

exactly.

Answer 10

only implicit diferntiation..thn wat does the d^2 n all mean?

Answer 11

the squared means you do it tiwce. so you differentiate once, then do it again.

Answer 12

n thn its over dx^2?..wat does tht mean?

Answer 13

same thing, just done twice.

Answer 14

ohh..ok..thank u soo much..rlly helps.. i wish thy jus wrote do the second deriv!

Answer 15

basically when you with d^2(some function)/dx^2, you are differentiation the function in terms of x, then differentiating it again.

Answer 16

\[\frac{d^2}{dx^2}=\frac{d}{dx}*\frac{d}{dx}\]
Which means, effectively, take the second derivative. You can also take your function and solve it explicitly and avoid implicit completely.
1-xy=x-y
1-x=xy-y
1-x=(x-1)y
y=(1-x)/(x-1)
y=-(x-1)/(x-1)
y=-1
the second derivative would be zero.

Answer 17

Solve for x:
-(x+xy)=-(y+1)
x(y+1)=(y+1)
x=1
The second derivative of that would also be zero.

Answer 18

ohhok...understood:)! thank u so much!