Mathematics OpenStudy (anonymous):

find d^2*y/dx^2 in terms of x and y for 1-xy=x-y?plzz:)..dont rlly understand what its asking:( OpenStudy (anonymous):

this is asking for hte second derivative. So take the derivative of the derivative. OpenStudy (anonymous):

$d ^{2}y/dx ^{2}$ OpenStudy (anonymous):

so first solve for y in terms of x. OpenStudy (anonymous):

thts wat it says on the paper OpenStudy (anonymous):

hm. OpenStudy (anonymous):

are you sure:$1-xy=x-y$ is the equation? OpenStudy (anonymous):

yes OpenStudy (anonymous):

Implicit differentiation! OpenStudy (anonymous):

exactly. OpenStudy (anonymous):

only implicit diferntiation..thn wat does the d^2 n all mean? OpenStudy (anonymous):

the squared means you do it tiwce. so you differentiate once, then do it again. OpenStudy (anonymous):

n thn its over dx^2?..wat does tht mean? OpenStudy (anonymous):

same thing, just done twice. OpenStudy (anonymous):

ohh..ok..thank u soo much..rlly helps.. i wish thy jus wrote do the second deriv! OpenStudy (anonymous):

basically when you with d^2(some function)/dx^2, you are differentiation the function in terms of x, then differentiating it again. OpenStudy (anonymous):

$\frac{d^2}{dx^2}=\frac{d}{dx}*\frac{d}{dx}$ Which means, effectively, take the second derivative. You can also take your function and solve it explicitly and avoid implicit completely. 1-xy=x-y 1-x=xy-y 1-x=(x-1)y y=(1-x)/(x-1) y=-(x-1)/(x-1) y=-1 the second derivative would be zero. OpenStudy (anonymous):

Solve for x: -(x+xy)=-(y+1) x(y+1)=(y+1) x=1 The second derivative of that would also be zero. OpenStudy (anonymous):

ohhok...understood:)! thank u so much!

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