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OpenStudy (anonymous):
Find the roots of x^2-x=6 algebraically, please explain.
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OpenStudy (anonymous):
(x-3)(x+2)
OpenStudy (anonymous):
Ok so (x-3)(x+2)=0
OpenStudy (saifoo.khan):
yeah
OpenStudy (saifoo.khan):
x = 3 or x = -2
OpenStudy (anonymous):
ok 1st you find two numbers which you can multiply and get 6...which are 6 and 1 ...3and 2....but you must find numbers which when subtracted you will get -1...from -x...so its 3 and 2 but the 3 must be negative.
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OpenStudy (anonymous):
so x=3 or -2
OpenStudy (anonymous):
Ohh alright thanks!
OpenStudy (anonymous):
you are welcome
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