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OpenStudy (anonymous):
Hi guys, can you soulve this please?
My Assignment...
y-2x=3
3x+y=9
Substitution?

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OpenStudy (saifoo.khan):
use eliminatiom

OpenStudy (saifoo.khan):
elimination

OpenStudy (anonymous):
--um...im just a beginner...? i need the coordinates?

OpenStudy (anonymous):
elimination y-y+-2x-3x=3-9
so -5x=-6
so x=6/5
then you can subts the x-value in either one of the equations to get y=27/5
hope i helped

OpenStudy (anonymous):
you can subtract the entire equations from each other, leaving 5x=6 (or x=6/5) and then put it in for x so y-12/5=3 which makes y "5and2/5"

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OpenStudy (anonymous):
argh you beat me.

OpenStudy (anonymous):
lol

OpenStudy (saifoo.khan):
x = -3/11
y = 27/11

OpenStudy (anonymous):
--nice...i hope im like you....
thanks!

OpenStudy (anonymous):
khan please redo the problem

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OpenStudy (anonymous):
saifoo, you're wrong. 27/11-9/11=18/11 which is not 9

OpenStudy (saifoo.khan):
i usd ny calc. :O

OpenStudy (saifoo.khan):
my*

OpenStudy (anonymous):
\[y=2x+3\]
\[3x+2x+3=9\]
\[5x=6\]
\[x=\frac{6}{5}\]

OpenStudy (anonymous):
it lied. My calculator lies to me all the time. I have to send it to bed without dinner.

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OpenStudy (anonymous):
lol jibble you crack me up

OpenStudy (anonymous):
\[3\times \frac{6}{5}+y=9\]
\[frac{18}{5}+y=9\]
\[y=9-\frac{18}{5}\]
\[y=\frac{27}{5}=5.4\]

OpenStudy (anonymous):
you can just remove its battery and wait for it to come and apologise

OpenStudy (anonymous):
I'd probably be waiting for a while, huh?

OpenStudy (anonymous):
lol ya while you wait it will be learning its lesson

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