Let C be the circle(x-1)2+(y-2)2=144 and P be the point P(10,10). Which of the Following is true? A.P is the center of C B. P is inside C, but not the center of C C. P is outside C D. P is on C E. The location of P relative to C cannot be determined How do you get the answer?
\[(x-1)^2+(y-2)^2=144\] a circle with center (1,2) and radius 12
so A is surely out. if it is on the circle that means the distance between (1,2) and (10,10) is 12, which you can check by pythagoras: \[9^2+8^2=145\] which is not 144! so not on the circle
in fact it tells you that (10,10) is outside the circle because the distance between (1,2) and (10,10) is bigger than 12, the radius
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