Let C be the circle(x-1)2+(y-2)2=144 and P be the point P(10,10). Which of the Following is true?
A.P is the center of C
B. P is inside C, but not the center of C
C. P is outside C
D. P is on C
E. The location of P relative to C cannot be determined

How do you get the answer?

Question

Let C be the circle(x-1)2+(y-2)2=144 and P be the point P(10,10). Which of the Following is true?
A.P is the center of C
B. P is inside C, but not the center of C
C. P is outside C
D. P is on C
E. The location of P relative to C cannot be determined

How do you get the answer?

anonymous · Answer

$$(x-1)^2+(y-2)^2=144$$ a circle with center (1,2) and radius 12

anonymous · Answer

so A is surely out.  if it is on the circle that means the distance between (1,2) and (10,10) is 12, which you can check by pythagoras:
$$9^2+8^2=145$$ which is not 144!  so not on the circle

anonymous · Answer

in fact it tells you that (10,10) is outside the circle because the distance between (1,2) and (10,10) is bigger than 12, the radius