Ask
your own question, for FREE!
Mathematics
55 Online
Let C be the circle(x-1)2+(y-2)2=144 and P be the point P(10,10). Which of the Following is true? A.P is the center of C B. P is inside C, but not the center of C C. P is outside C D. P is on C E. The location of P relative to C cannot be determined How do you get the answer?
Still Need Help?
Join the QuestionCove community and study together with friends!
\[(x-1)^2+(y-2)^2=144\] a circle with center (1,2) and radius 12
so A is surely out. if it is on the circle that means the distance between (1,2) and (10,10) is 12, which you can check by pythagoras: \[9^2+8^2=145\] which is not 144! so not on the circle
in fact it tells you that (10,10) is outside the circle because the distance between (1,2) and (10,10) is bigger than 12, the radius
Can't find your answer?
Make a FREE account and ask your own questions, OR help others and earn volunteer hours!
Join our real-time social learning platform and learn together with your friends!
Join our real-time social learning platform and learn together with your friends!
Latest Questions
ShinePrincess:
Write a function that will create the following transformation. Shift f(x) down 3
forgetmylife:
Only the real understand ud83eudd26ud83cudffdu2642ufe0f I'm tired. Tired of the constancy, the constancy of judgment.
rishavraj:
Just trying to find a friend. We met on openstudy, her nickname on there was something "tarantula".
58 minutes ago
0 Replies
0 Medals
11 hours ago
2 Replies
1 Medal
2 hours ago
4 Replies
0 Medals