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OpenStudy (anonymous):

If cosh x= 5/3 with x<0, find the values of the other five hyperbolic functions.

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OpenStudy (anonymous):

like with sine and cosine but instead use \[ \cosh^2(x) - \sinh^2(x) = 1\]so \[\sinh^2(x)=\cosh^2(x)-1\] \[\sinh(x)=\pm\sqrt{\cosh^2(x)-1}\] substitute and get \[\sinh(x)=-\frac{4}{3}\] (negative because x is)

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