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whats the domain of g(x) = sqrt of (7-3x) ?
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negative infinity, 2)
i know that to make it zero it is 7/3
yep that sound more like it. \[(-\infty,\frac{7}{3})\]
\[7-3x\geq 0\] \[7\geq 3x\] \[\frac{7}{3}\geq x\]
k thanks so much!
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