Mathematics 29 Online
OpenStudy (anonymous):

find lim x->infinity (1-2x^2)/(3x^3+x)

OpenStudy (anonymous):

use l'Hôpital's rule: http://en.wikipedia.org/wiki/L'H%C3%B4pital's_rule until you get -4/18x which gives you lim (x->infinity)=0

OpenStudy (mathteacher1729):

I don't know how much work they require you to show or what they accept in terms of work shown, but you can note that the power in the denominator is greater than the power in the numerator so ignoring constants you essentially have lim x goes to infinity x^2 / x^3 which is really 1 / x ... and we all know lim x goes to infinity of 1 / x = 0. :) Hope this helps.

OpenStudy (anonymous):

Yes,\[ax ^{m}/ax ^{n}\]m<n, lim goes to 0

Latest Questions
abound: Wow question cove really fell off
1 hour ago 4 Replies 1 Medal
ayden09: chat i love black pink hehe i like jones to
15 hours ago 19 Replies 2 Medals
kamani7676: help
20 hours ago 5 Replies 1 Medal
kamani7676: Help
20 hours ago 76 Replies 2 Medals
sigmasimmymind: need help
23 minutes ago 10 Replies 2 Medals
notmeta: (communication unit) help??????????????
22 hours ago 3 Replies 0 Medals