Question

In triangle ABC, the ratio of the angle is A:B:C=2:3:4. What is the measure of the smallest angle?

Answer 1

the smallest angle is opposite the shortest side

Answer 2

and we can calculate that angle using a modifies law of cosines

Answer 3

\[cos^{-1}\left(\frac{short^2 - side^2-other.side^2}{-2(side)(other.side)}\right)=angle\]

Answer 4

\[cos^{-1}(\frac{2^2 -3^3-4^2}{-2(3)(4)})=angle\]
\[cos^{-1}(\frac{4 -9-16}{-24})=angle\]
\[cos^{-1}(\frac{11}{24})=angle\]

Answer 5

helps to know how to add... let me fix that

Answer 6

\[cos^{-1}(\frac{21}{24})=abt.\ .5054^o\]

Answer 7

um thats not any of the choices (1)20 (2)40 (3)60 (4)80

Answer 8

may calc was on radians :)

Answer 9

\[2^2 = 3^2 + 4^2 -2(3)(4)\ cos(a)\]
\[4 = 9 + 16 -24\ cos(a)\]
\[4-9-16 = -24\ cos(a)\]
\[-21/-24 = cos(a)\]
\[cos^{-1}(21/24) = a\]
or at least it should right?

Answer 10

that equals about 30 degrees

Answer 11

but thats aint a choice is it

Answer 12

nope

Answer 13

the next biggest one =

9-4-16 11
------- = ---- ; cos-1(11/16) = abt 47 degrees
-2(2)(4) 16

30 + 47 = 77

180
-77
----
103

Answer 14

those are the answers; but your choices are either mistyped, or someone messed it up in the program :)

Answer 15

lol its a prep regent

Answer 16

28.955 degrees is the smallest angle tho ;) good luck with it

Answer 17

lol thanks for trying