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OpenStudy (anonymous):
\[7^{2\log_{2}16 }\]
Evaluate this! :P
OpenStudy (anonymous):
What's log 16 base 2?
OpenStudy (anonymous):
is that the same as 2^x = 16 find x? (for GoBlue_)
OpenStudy (anonymous):
yes, yes it is :)
OpenStudy (anonymous):
good, cause i also have an exam tomorrow :P
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OpenStudy (anonymous):
lol paulz are you from Colonel By?
OpenStudy (anonymous):
nah i wish... then i would be doing an easier exam
i think
are you in grade 12?
if so i would have to be 7 years younger too
OpenStudy (anonymous):
is that school in canada?
OpenStudy (anonymous):
\[16=2^4\]
OpenStudy (anonymous):
\[2^{(4*2)}= x\]
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OpenStudy (anonymous):
wel know this one already....::)
OpenStudy (anonymous):
\[2^8=x\]\[x=256\]
OpenStudy (anonymous):
what happen to the 7 and the log?
OpenStudy (anonymous):
CM ignored it.
OpenStudy (anonymous):
A noble strategy.
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OpenStudy (anonymous):
are you suppose to ignore it?
OpenStudy (anonymous):
so the whole thing should be
7^2(log(2)(16)) or "seven to the power of all of two multiplied by log base two, sixteen close bracket"
or 7^(2*4)
or 7^8
or 5764801
OpenStudy (anonymous):
no you aren't supposed to ignore it. it was just a mistake.