in a triangle two sides that measure 6cm and 10cm form an angle that measures 80 degrees. Find to the nearest degree measure of smallest angle of triangle. I found the remaining side was 12 using law of cosines, then tried to use law of sine to find remaining angle but it's not working out, help?
the smallest angle will be opposite the smallest side, 6cm
yeah i figured that part out but when i plugged in 12 / sin 80 = 6 / sin x and solved to find the degree it came out to a negative number, so im not sure what i'm doing wrong?
oh wait i figured out what i was doing wrong, thanks for the help tho!
i got sin of angle = 0.4924
yeah and then you change do sin^-1 (.4924 etc) to get the degress but stupid me had my calculator in radians mode...bleh
oh ! ok
we're all human guy!
lol yup but thanks for the help :)
yw
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