To determine the number of deer in a game preserve, a conservationist catches 871 deer,tags them and lets them loose. Later 496 deer are caught; 248 of them are tagged. How many deer are in the preserve?
1119... is that right?
I meant if 496 deers are caught and 248 are tagged, then 496-248=248 are the ones that are not tagged..
To determine the new total, you must find the "newly" tagged deer. 496 - 248 = 248 This now must be added to the original amount. 871 + 248 = 1119
but maybe it's just: 871+496 = 1367
I am not sure which one it would be?
what i mean 248 of them are tagged.. he doesn't say tagged AGAIN, maybe he caught a bunch of untagged deers and tagged them all..
Originally there were 871 caught. The on the second attempt, he caught a random group of 496 deer. 248 of these were already tagged from the past 871, but there are 496 - 248 = 248 new deer in the game preserve. So now add 871 + 248 to get the new total, or 1119.
Bobby, the question doesn't say, were ALREADY tagged.. it says 496 are caught and 248 tagged.. probably our first thoughts were right, i got 1119 the same way, but ughh it's just the wording of the question is stupid..
maybe they still didn't even catch all the deers haha..
but yea prbbly 1119 is correct..
yes 1119 is correct
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