Question

Find the equation of the line that contains the point (-4, 18) and is parallel to the line that contains (2, -2) and (6, 3)
y=mx+b form, do not use decimals. Leave improper fractions improper. help?

Answer 1

x1=2 , y1=-2
x2=6 , y2 = 3

the eqn of line passing through (x1,y1) and (x2,y2) can be written as ;

(y2-y1)/(x2-x1) = (y-y1)/(x-x1)

substituting (x1,y1) and (x2,y2) in above eqn we get ;

5/4 = (y+2)/(x-2)
which gives us ,
y=(5/4)*x - (9/2)

any line parallel to above line must have same slope and can be written as
y=(5/4)*x + c ( 'c' has to be determined )
this line passes through (-4,18) hence x=-4 and y = 18 must satisfy it

18 = (5/4)*(-4) + c
therefore c = 23
hence the required eqn is , y = (5/4)*x + 23

Answer 2

O wow, thank you!

Answer 3

ok its telling me ths is wrong, i guess im not distributing the 5/4 properly