Tell whether f(x) = - x2 - 5 is an even or odd function, and describe its symmetry.

even: symmetric with respect to the origin
even: symmetric with respect to the y-axis.
odd: symmetric with respect to the origin
odd: symmetric with respect to the y_axis

Question

Tell whether f(x) = - x2 - 5 is an even or odd function, and describe its symmetry.

even: symmetric with respect to the origin
	even: symmetric with respect to the y-axis.
	odd: symmetric with respect to the origin
	odd: symmetric with respect to the y_axis

anonymous · Answer

f(x) is even if
$$f(-x) = f(x)$$

f(x) is odd if
$$f(-x) = -f(x)$$

So plug in (-x) for x in the function$$-x^2-5$$

Do you get -f(x) or f(x)?