Question

Determine a polynomial equation whose roots include the given values: 5,-5,1,-1

Answer 1

\[(x ^{2}-5^{2})(x ^{2}-1)=0\]

Answer 2

can you explain how you got there?

Answer 3

now when you hav the roots to an equation
as a. b etc... to get the equation you have to multiply by x-(root1)*x-(root2) and so on

Answer 4

ahhhhh, ok cool!

Answer 5

(x-a)*(x-b)

Answer 6

for your values u get (x-5)(x+5)(x-1)(x+1)=0

Answer 7

(a-b)*(a+b)=a^2-b^2

Answer 8

expand and voila you get your equation

Answer 9

take the roots as \[\alpha , \beta , \gamma , \delta\]

Answer 10

then apply formula of quadratic eqn as u do for x^2 + (-b/a)x + c/a

Answer 11

hey divya if u ever come back again
physics_him@hotmail.com