Question

7x=5y Find the slope and the y intercepts of each line whose equation is given?

Answer 1

You want to put it in Slope-Intercept Form, which is y=mx+b.
m=Slope
b=y-intercept

Answer 2

ok y intercept is 0?

Answer 3

Correct!

Answer 4

so how do i get from 7x=5y to Y=(7/5)x+0

Answer 5

You're just isolating the y by itself... so you divide each side by 5. That leaves you 7/5x=y

Answer 6

how do i lose the x?

Answer 7

You don't. The x is part of the ordered pair (x,y) for the equation.

Answer 8

Are you still looking for the slope?

Answer 9

no i just know that 7/5 is the slope and 0 is the intercept.. didnt know if the x is 7/5 and y is o?

Answer 10

No. It's 7/5 times x equals y. In the full Slope-Intercept Form, it's 7/5x+0=y
Where 7/5 is the slope, and 0 is the y-intercept.

Answer 11

ok so sorry i dont get this stuff. if 7/5 is times x, where did x go? is x =1?

Answer 12

x is whatever. the x and y in the equation is any ordered pair. If you're only looking for the y-intercept and the slope, the x doesn't matter. As long as you realize that the slope is coefficient of x.

Answer 13

oh ok. got it.. thanks.. can u help with this one too? this is my last week in principles in algebra and i have to pass to go on to next class. I promise, I will not get a job requiring this stuff!! lol here is problem....Write an equation of the line containing the specified point and perpendicular to the indicated line
(4, −2), x = 1

Answer 14

Okay. Sorry, this is taking me a minute. lol

Answer 15

oh ok.. lol i understand and this isnt even my final! lol just two questions..

Answer 16

For lines to be perpendicular, the slope of line one times the slope of line two must equal -1.

Answer 17

ok? lol well i have to go attend to the kiddos..lol i will have to come back tomorrow for more help.. if you are here i will holla at ya! thanks so much for your help so far!

Answer 18

No problem. Glad I could help a little!