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Mathematics 18 Online
OpenStudy (anonymous):

x2 – 8x + 15

OpenStudy (saifoo.khan):

x = 5 x = 3

OpenStudy (anonymous):

How do you show work to that problem

OpenStudy (anonymous):

\[x^2-3x-5x+15\]

OpenStudy (anonymous):

(x-3)(x-5)

OpenStudy (anonymous):

Set both sides to zero, x=3, x=5

OpenStudy (anonymous):

Ehhhh !!

OpenStudy (anonymous):

That help?

OpenStudy (anonymous):

ohhh !! i get it you combine like terms rite

OpenStudy (anonymous):

I used the AC method to factor it

OpenStudy (anonymous):

whats that ?

OpenStudy (anonymous):

Nevermind the AC method, different problem, lol, I factored it.

OpenStudy (anonymous):

Are you factoring or solving for x?

OpenStudy (anonymous):

factoring

OpenStudy (anonymous):

then (x-3)(x-5) is your answer You find the two numbers that when multiplied = 15 but when added = 8, 3 & 5.

OpenStudy (anonymous):

8 is negative and 15 is positive so both of your numbers have to be negative. negative times negative = positive and negative plus negative is negative. Get it?

OpenStudy (anonymous):

Hmmm

OpenStudy (anonymous):

What do you not understand?

OpenStudy (anonymous):

im kinda getting it

OpenStudy (anonymous):

ok, if you are happy with my answer, please click good answer.

OpenStudy (anonymous):

were at ?

OpenStudy (anonymous):

the right side of the grey line my name is in

OpenStudy (anonymous):

still didnt find it lol

OpenStudy (anonymous):

see my name? look on the other side of that bar. Its ok if you dont find it.

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