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see power gain =20 20 = 10log (Po/Pi) 2 = log (Po/Pi) so Po/Pi = 100 Pi = Po / 100 = 12/100 = .12 watts
u got it?
not quit, i dont get the solving
20 = 10log (Po/Pi) get this?
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ya i get it tell the second group where u get 100?
see if log x = 2 then wht is x equal to?
huh?
if log x = 2 then x = 100 do u get it>
no lol could you work that or how y does it = 100 sorry
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wht do u know abt logarithms?
\[\log_{b}a = x => a = b^{x} \]
u understand?
could you do that but with are numbers
see if \[\log_{10}x = 2 => x = 10^{2}\]
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got it!
so now u get ur question or not?
yeah ill post another when i solve and ask for u to check it
ohk..be sure to try it urself 4 times b4 posting it
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