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Mathematics 18 Online
OpenStudy (anonymous):

HELP PLEASE HAVE TONE MORE UPLOADED

OpenStudy (anonymous):

OpenStudy (anonymous):

see power gain =20 20 = 10log (Po/Pi) 2 = log (Po/Pi) so Po/Pi = 100 Pi = Po / 100 = 12/100 = .12 watts

OpenStudy (anonymous):

u got it?

OpenStudy (anonymous):

not quit, i dont get the solving

OpenStudy (anonymous):

20 = 10log (Po/Pi) get this?

OpenStudy (anonymous):

ya i get it tell the second group where u get 100?

OpenStudy (anonymous):

see if log x = 2 then wht is x equal to?

OpenStudy (anonymous):

huh?

OpenStudy (anonymous):

if log x = 2 then x = 100 do u get it>

OpenStudy (anonymous):

no lol could you work that or how y does it = 100 sorry

OpenStudy (anonymous):

wht do u know abt logarithms?

OpenStudy (anonymous):

\[\log_{b}a = x => a = b^{x} \]

OpenStudy (anonymous):

u understand?

OpenStudy (anonymous):

could you do that but with are numbers

OpenStudy (anonymous):

see if \[\log_{10}x = 2 => x = 10^{2}\]

OpenStudy (anonymous):

got it!

OpenStudy (anonymous):

so now u get ur question or not?

OpenStudy (anonymous):

yeah ill post another when i solve and ask for u to check it

OpenStudy (anonymous):

ohk..be sure to try it urself 4 times b4 posting it

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