What is the equation of the line, in general form, that passes through (1, 2) and is parallel to the line whose equation is 3x - 4y + 12 = 0?

Question

bahrom7893 · Answer

So first let's rewrite the line:
3x-4y+12=0
-4y = -12-3x
4y = 12+3x
y = (3/4)x + 3

anonymous · Answer

ok got that

bahrom7893 · Answer

Now if the lines are parallel the slopes must be the same, so the sloep is:
M = 3/4

anonymous · Answer

ok is that it?

bahrom7893 · Answer

Not yet, now find the equation of  the line you need:
y-y1 = m(x-x1)
y - 2 = (3/4)(x-1)

bahrom7893 · Answer

y - 2 = (3x/4) - (3/4)
y = (3/4)x - (3/4) + 2
y = (3/4)x - (3/4) + (8/4)

bahrom7893 · Answer

y = (3/4)x + (5/4)
or 
y = (1/4) (3x + 5)

bahrom7893 · Answer

or 
4y = 3x + 5, or
4y-3x-5=0.. whichever form you want.. all of the last 4 lines are the same..

anonymous · Answer

thanksss so ,much and tahank you for helpin me!