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what is the excluded value? 3x(_over)/1-3x
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\[\left(\begin{matrix}3x \\ 1-3x\end{matrix}\right)\]
x=1/3
x=1/3 would be exc;ided as ot wwould result in division by zero
1/3
\[\frac{3x}{1-3x}\] is only valid when the denominator (bottom) is not zero. So the excluded value is when 1 - 3x = 0.
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check out the graph: http://bit.ly/kmZoIC You can see at x=1/3, it "blows up." It will approach negative infinity coming from one direction and positive infinity coming from the other. At exactly x=1/3, the function is undefined.
so its 1over3?
yes.
Nice graph, I bookmarked that page.
desmos.com is pretty awesome for a lot of questions here...
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