Question

Ok, one more...limit as x approaches 0 of (e^x+x)^1/x?

Answer 1

[x]' = 1 ... so thats covered :)

Answer 2

err... is the exponent ^(1/x)?

Answer 3

(1+0)^înf = 1

Answer 4

yes

Answer 5

http://www.wolframalpha.com/input/?i=limit+as+x+approaches+0+of+%28e^x%2Bx%29^1%2Fx

goes to e^2 if this is right

Answer 6

lim_(x->0) (e^x+x) = 1

Answer 7

e^(x+x)^(1/x) = e^(2x)*(1/x) = e^2

Answer 8

yep, the e^2 is the right answer

Answer 9

e^2

Answer 10

Just slot some figures in...