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Mathematics 19 Online
OpenStudy (anonymous):

x^2-x+3=0 x=?

OpenStudy (anonymous):

[(1+i sqrt{11})/2, and (1-i sqrt{11})/2]

OpenStudy (anonymous):

i don't understand.. :(

OpenStudy (anonymous):

do i not factor that out and set them to 0?

OpenStudy (anonymous):

quadratic formula

OpenStudy (anonymous):

the discriminant is negative so you cannot factor over the real numbers

OpenStudy (anonymous):

\[1\sqrt{11}/2 \]? and one for negative?

OpenStudy (anonymous):

yes, 1 + and 1- sqrt{11}/2

OpenStudy (anonymous):

thanks!

OpenStudy (anonymous):

No problem

OpenStudy (anonymous):

how would it be written in an a+bi way?

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