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Use the Pythagorean theorem to find the length of the hypotenuse with one side measuring 16 feet and the other measuring 7 feet.
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The Pythagorean theorem states : a² + b² = h² with a,b length of the adjacent sides to the right angle, and h length of the hypotenuse. Then, you got : 16² + 7² = h² which you can simply solve.
\[c ^{2} = a^2 + b^2 \] \[c ^{2} = 16^2 + 7^2 \] \[c ^{2} = 256 + 49 \] \[c ^{2} = 301\] \[c =\sqrt[2]{30}\]
\[c = \sqrt{301}\] i mean.
\[a^2 + b^2 = c^2\] \[16^2 + 7^2 = c\] \[256 + 49 = c^2\] \[305 = c^2\] \[\sqrt{305} = c\] \[17.5 \approx c\]
@josephniel: You added 256 + 49 wrong o_0
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