Question

Could someone help me with (-45x^-8x^6y^4z^0/9x^2y^-2z)^-2 PLEASE!

Answer 1

ooh man... u need the simplified version of this?

Answer 2

I can't tell what's being multiplied and what's an exponent.

Answer 3

Does this help?

Answer 4

Yes.

First thing to do is work within the parenthesis.

The numbers are easy: -45/9 gives us -5.

For exponents, we add them if multiplying, subtract them if dividing. So with x, -8 + -6 - 2 = -16. Likewise for y and z.

At this point you should have (-5*x^(-16)*y^(6)*z^(-1))^(-2).

Now you can distribute the ^(-2) across each term:

(-5)^(-2) = 1/25 (or 1/(5^2))

x^(-16*-2) = x^32

y^(6*-2) = y^(-12) (or 1/(y^(12))

z^(-1*-2) = z^2

So you should end up with:

((x^32)*(z^2))/(25(y^12)).

Of course, you should also double check this to make sure I did it right in my head and to make sure you understand the process.

Answer 5

Grr....docx