Question

Sharon has two solutions available in the lab, one with 6% alcohol and another with 14% alcohol. How much of each should she mix together to obtain 10 gallons of a solution that contains 12% alcohol?
I'm having trouble coming up with the equation?

Answer 1

let x for 6%
let y for 14%
x+y=10
0.06x+0.14y= 10*0.12

Answer 2

x+y=10
y=10-x
substitution y=10-x
0.06x+0.14(10-x)= 10*0.12
I think u can solve from here

Answer 3

Thanks for all the help

Answer 4

0.06x+0.14(10-x)= 10*0.12
0.06x+1.4-0.14x= 1.2
-0.08x = 1.2-1.4
x = -0.2/-0.08
x = 2.5
substitution x= 2.5 find y
x+y=10
2.5+y=10
y= 10-2.5
y= 7.5
14% need 7.5 alcohol
6% need 2.5 alcohol
you check calculator made sure I'm not calculator wrong