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find the x-intercept, y-intercept and the vertical asymptote of g(x)=ln(x+1)
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x-intercept set y=0 (g(x)=y)) 0=ln|x+1| 1=x+1 x=0 so the x intercept is (0,0) so the y-intercept is (0,0) also
vertical asymptote: x+1 = 0 x = -1
right cow :)
thank you
x-intercept, y=0 0=ln(x+1) 1=x+1 x=0, y-intercept, x=0 g(x)=ln(1) =0 vertical asymptote, when x is not in the domain, since \[x \le-1\] is not in the domain, so the asymptote is when x=-1
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