Question

In a regular pentagon ABCDE and regular hexagon MNOPQR, 2AB = 3MN and CD + QR = 10. Which is 4BC + 5PQ?

Answer 1

Well start by realizing that the shapes are regular, so all the sides of the pentagon are the same, right? So AB = BC = CD = DE = EA

Answer 2

yes and then you can get two simultaneous equations in AB and MN which can be solved to find measure of AB and MN

Answer 3

and AB = BC and MN = PQ so u can plug these into find the value of 4BC + 5PQ

Answer 4

understand that or need more help?

Answer 5

I would just call the side length for the pentagon x and the sidelength for the hexagon y. Then you substitute into the given equations to get 2x = 3y and x+y = 10

Answer 6

thats fine

Answer 7

that not it but thanks doe....

Answer 8

That's the first step, Chrissy. You still have to solve for x and y.