In a regular pentagon ABCDE and regular hexagon MNOPQR, 2AB = 3MN and CD + QR = 10. Which is 4BC + 5PQ?

Question

anonymous · Answer

Well start by realizing that the shapes are regular, so all the sides of the pentagon are the same, right? So AB = BC = CD = DE = EA

anonymous · Answer

yes and then you can get two simultaneous equations in AB and MN which can be solved to find measure of AB and MN

anonymous · Answer

and AB = BC and MN = PQ so u can plug these into find the value of 4BC + 5PQ

anonymous · Answer

understand that or need more help?

anonymous · Answer

I would just call the side length for the pentagon x and the sidelength for the hexagon y. Then you substitute into the given equations to get 2x = 3y and x+y = 10

anonymous · Answer

thats fine

anonymous · Answer

that not it but thanks doe....

anonymous · Answer

That's the first step, Chrissy. You still have to solve for x and y.