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In y +a(x-h)^2+k the vertex is at (h,k). true or false?
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true;
why is true?
coz h is x & k is y. lol.
is that suppose to be y=a(x-h)^2+k
no. . .
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no equal sign?
then i would say false since what you have above is not an equation
y=a(x-h)^2+k has vertex (h,k) y+a(x-h)^2+k is just an expression not an equation
thanks!
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