Given f′′′(x)=e^x with f′′(0)=7, f′(0)=5, then f(x)= _______+c
f''(x)=e^x+D f''(0)=e^(0)+D=7 1+D=7=> D=6 so we have f''(x)=e^x+7 f'(x)=e^x+7x+A f'(0)=e^(0)+7(0)+A=5 1+0+A=5=>A=4 so we have f'(x)=e^x+7x+4 f(x)=e^x+7x^2/2+4x+C
I believe that the coefficient of the x^2 term should be 3, not 7/2. f(x) = e^x + 3 x^2 + 4 x + c Derivative of (e^x + 3 x^2 + 4 x + c) = e^x + 6 x + 4 When x = 0, 1 + 0 + 4 = 5 The second derivative of f(x) is e^x + 6 When x = 0, 1 + 6 = 7 The third derivative of f(x) is e^x
yea i got D=6 and for some reason i write 7 if they alittle about what they are doing then the will see that i had D=6 and accidently replaced it with 7
I will be 77 years old in August and cannot integrate x with pencil and paper. Once knew the basic rules in the 50's, but not today. Therefore, I rely on Mathematica to do the clerical work, an activity viewed by some as sort of, cheating. Look, the only reason I wrote the last sentence was to respond to a possible veiled insinuation that "if they alittle about what they are doing then the will see that i had D=6 and accidently replaced it with 7", where the word "they" in your mind could and should be replaced with the word "you". You might be interested in the following video: "Teaching kids real math with computers: Conrad Wolfram on TED.com" http://blog.ted.com/2010/11/15/teaching-kids-real-math-with-computers-conrad-wolfram-on-ted-com/
i was just saying a may a little typ-o and it is an obvious typ-o anyone should be able to see 6 does not equal 7
Join our real-time social learning platform and learn together with your friends!