Question

A man who is heterozygous for tongue rolling and has a normal vision and a woman who cannot roll her tongue and is heterozygous for colorblindness have a child. What is the probability that it will be able to roll his/her tongue and have normal vision? Tongue-rolling is due to a dominant allele. Color Blindness is caused by an X-linked recessive gene.

Answer 1

Tongue-rolling is due to a dominant allele-
phenotype of father-Rr
phenotype of mother-rr
phenotype of children-Rr,Rr,rr,rr
50% chance of tongue roll in children.

colour blindness
x linked recessive--->25% chance of a child with colour blindness.
The probability that it will be able to roll his/her tongue and have normal vision might be 25% ----Not sure

.........................sorry Forgot every thing........

Answer 2

thank you for taking your time to answer! I know many people hate genetics.. haha

Answer 3

The probability that a child born to these parents is able to roll their tongue and have normal vision is 1/8.

Probability of tongue roll is 1/2 (or 2/4) and probability of color blindness is 1/4. So you multiply these probabilities to find the probability that the child has both. 2/4 * 1/4 = 2/16 or 1/8

Answer 4

men( dominant) female (recessive )
X(R)-Y X(r)-X(r) = 2 X(R) X(r) +2Y X(r)
so the girls will not have the blind and all the sons will have the blind
that's what i think because the dominant R from the father will stop the recessive one in girls but the Y from the father as we know doesn't not have an allele .. so the allele will only come from the mom in males !