Question

One x-intercept for a parabola is at the point (2,0). Use the Quadratic formula to find the other x-intercept for the parabola defined by this equation: y=4^2-4x-8

Answer 1

You mean y=4x^2-4x-8point!?
(2,0) means that x=2 when y=0, so you need to know the second salution, when y=zero.

So find it with \[x_{1,2}=(-b \pm \sqrt{D})/2a = (4 \pm 12)/8 = 2; -1\]

Answer 2

the second point is (-1, 0)

Answer 3

x1 +x2 = -b/a....where c and a are coefficients this gives us x2 = 4/4 - 2

Answer 4

id21 is correct