Question

Find the area under P=90(0.7)^t between t=0 and t=6. please help!Medals are awarded!

Answer 1

90*(0.7)^6/ln0.7

Answer 2

Area under a curve can be found my integrating that curve. Set up your integral with the limits given, 0 and 6.

\[\int\limits_{0}^{6}90(0.7)^tdt = 90\int\limits_{0}^{6}(0.7)^tdt\]

Answer 3

\[90\int\limits_0^6 0.7^t \, dt\]

Answer 4

why is it natural log and the other post 900 though?

Answer 5

900 was wrong. A mistype.

Answer 6

I meant 90 0.7 but space did not appear

Answer 7

okay:) but why is it natural log?

Answer 8

\[\int 0.7^tdt = \int e^{t \log{0.7}} = \frac{e^{t \log{0.7}}}{\log{0.7}} = \frac{0.7^t}{\log{0.7}}.\]

Answer 9

hello every one i have given the correct ans...every1 is wrong