please show work
please reply!!!!
arcAD = 80; angAOB = 100 arcAB = 100; angC = 50 arcABD = 100+80 = 180 , and its a chord thru the center soo andBAO = 40 since 40+100 +x = 180
can you show the work?
not really since this isnt a graphic interface
is there any work?
central angles sweep out equal measures of arcs inscribed angles sweep out an arc that is double.
follow that measures from 1 to the end ...
ty
amistre64 can you explain more?
can you show the work more instead of just the answers
not really, thats as basic as I can state it
40 creates 80 80 creates 80 in the center 80 + 100 = 180 100 center creates 100 arcwhich creates a 50 angle ....
what do you mean my creates
like where do you get the 100 from
i mean that when I draw in here to show any work it doesnt really translate well into text :)
the hundred comes from the other part of the 180 that the 80 is attached to
inscribed angles produce arcs of 2x their measure center angles produce arcs of equal measure....
and the measures are inverses of each other so that if you know one you can get to the other
ok how about for #12? how do you get that
since you have a chord going straight thru the center of a cirlce; that divides it in half. 360/2 = 180
is it supposed to be 180 or 280?
depends on your definition of half of a circle i spose. id go with 180 meself
ok
amistre64, i have a couple more similar questions....ill write them as new questions so i can medal you
9) AD=twice time angle 1= 80 I was wrong number 9
since <1 = 40; arcAD = 2(40) = 80 since arcAD = 80, arcAB = 100 since arcAB=100, <AOB = 100 since arcAB = 100, <C = 100/2 = 50 since <1=40, <AOB = 100; and triangles add up anlges to 180, that leaves 40 left for <BAO
10) m<AOB = 180 - 80 m<AOB = 100
write em up :)
11) arc AB =< AOB =100
12) 180+100=280
13) <acb= 1/2 ARC AB = 100/2 = 50
14) m<BOA + m<1+ m<BAO = 180 100 + 40 + m<BAO = 180 m<BAO = 180 -( 100+40) = 180- 140 m<BAO = 40
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