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how do I solve for t in the equation x=9ln(3t) ?
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x/9 = ln(3t) 3t = e^(x/9) t = 1/3*e^(x/9)
To solve for t you raise e to the power of each side.
thanks
\[e^x = e^{9ln(3t)}\]\[\implies e^x = (e^{ln(3t)})^9\]\[\implies (3t)^9 = e^x\]\[\implies 3t = e^{\frac{1}{9}x}\]\[\implies t = \frac{1}{3}e^{\frac{1}{9}x}\]
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