solve for x: (2x-5)^{2}=11

Question

rosey · Answer

i nakey :)

anonymous · Answer

U can write this eq as 

2x -5 = (11)^1/2

And now solve for x..
Don't worry abt roots..... U should Know the right method :)

jhonyy9 · Answer

4x^2 -20x +25 =11
4x^2 -20x +14=0 /2
2x^2 -10x +7=0
              10+/- (radical 44)      2(5+/-radical 11)     5+/- radical 11
x_1,_2 = ---------------- = ---------------- = --------------
                        4                                 4                              2

anonymous · Answer

what

jhonyy9 · Answer

this is how do you need to do

jhonyy9 · Answer

- so but you can do it how have arote to you firstly  Ishaan94

anonymous · Answer

squeaky 22 i m trying to upload a file which is ur answer sorry it is not uploading

jhonyy9 · Answer

- than you will get those results too

anonymous · Answer

squeeaky What problem are u facing?

anonymous · Answer

my results were different

jhonyy9 · Answer

write here how you have got those results

jhonyy9 · Answer

Nancy - pardon but i think that you need to divid +/- radical 11 with2 too not just -only - 5 - check it please newly

anonymous · Answer

$$(2x-5)^2=11$$$$2x-5=\pm \sqrt{11}$$$$x= \frac{5\pm \sqrt{11}}{2}$$