Question

Solve p(x)=x^4 +6x^2 +9

Answer 1

There's nothing to solve there.

Answer 2

You probably mean solve p(x) = 0

Answer 3

isnt this where you do the (\[(x ^{2}+3)(x ^{2}+3)\]

Answer 4

In these you always define a variable to be x^2 and rewrite the function to be quadratic.

Answer 5

p(x) = x^4 +6x^2 +9 = 0
t^2 + 6t + 9 = 0, t=x^2
solve like you would a quadratic equation.

Answer 6

\[x^4+6 x^2+9=\left(x^2+3\right)^2 \] @arhendrickson Were you asking that your problem expression be factored in the first place?