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Solve : |2 – x| < 3
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\[|a| < b \iff -b < a < b\]
If you have one, you can rewrite it as the other.
So in this case you can re-write your problem as \[-3 < 2-x < 3\] Then you just solve simultaneously for the bounds of x.
Of course, don't try and use the opposite sign in the same rule...because it's not true that |a| > b => -b > a > b. For that you need to use an "or" a < -b OR a > b
-1,5?
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or -5,1?
-1,5 <----awnser
Keeping with polpak's response, -3 < 2 - x < 3 -5 < -x < 1 5 > x > -1 So, x is between -1 and 5.
Remember you have to switch the direction of the inequality when multiplying or dividing by a negative number.
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