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Mathematics 9 Online
OpenStudy (anonymous):

File attached, can someone help me solve this?

OpenStudy (anonymous):

OpenStudy (anonymous):

I can't open file

OpenStudy (anonymous):

its a word document

OpenStudy (anonymous):

Area a =(2x+5)*(x-2)+2x)

OpenStudy (anonymous):

Area of A=(2x+5)(2x+x-2)=(2x+5)(3x-2) =6x^2-4x+15x-10 =6x^2+11x-10

OpenStudy (anonymous):

u want A an B ?

OpenStudy (anonymous):

C) area for all shaded area = add two areas that you founded above together

OpenStudy (anonymous):

area B = (2x)*(2x-7)

OpenStudy (anonymous):

How is the Area of A (2x+5)^2?

OpenStudy (anonymous):

and what would all the area's equal? Area A + Area B?

OpenStudy (anonymous):

Area=length times width. You're multiplying length times length

OpenStudy (anonymous):

all shaded areas= add two areas together

OpenStudy (anonymous):

so (2x+5)^2+2x(2x-7) ?

OpenStudy (anonymous):

@GS it should be 6x^2+11x-10 + 2x(2x-7)

OpenStudy (anonymous):

oh ok, thanks. and for the last when it says check your work, and x=6. just plug it in?

OpenStudy (anonymous):

Area A: (2x+5)(2x+x-2)=(2x+5)(2x-2)=272 (when x=6) Area B: 2x(2x-7)=60 both areas= 332 (!) I was wrong before... sorry!

OpenStudy (anonymous):

k I'm so confused now LOL

OpenStudy (anonymous):

what is confusing?

OpenStudy (anonymous):

Well for the very last question, you plug in 6 for x. area A and area B at the end have to different answers, their both supposed to add up to the same number.

OpenStudy (anonymous):

inik has the right answer now, he just got messed up with the area was all

OpenStudy (anonymous):

Your answer for the last one should be 332 just like inik stated.

OpenStudy (anonymous):

ok sorry, I get it, I was confusing myself with a different concept aha. Thanks guys! (:

OpenStudy (anonymous):

this is your questions: D. When x = 6, the total area of the shaded portion of the diagram is 332 square units. Use x = 6 to verify your answer from part (c) above if you substitute x=6 in area for A & B & ADD them together you should have 332 & you do

OpenStudy (anonymous):

ok sorry, I get it, I was confusing myself with a different concept aha. Thanks guys! (:

OpenStudy (anonymous):

Great!!

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