a= 2 (b+c) solve for c
Ready to work on this together? Just lemme know when you're ready. :P
yes I am
Awesome. Let's do it then :D
First problem is that our C is stuck inside a parenthesis. How do we help it escape the parenthesis?
(Don't worry about your other questions yet. We'll work on those when we finish this one)
ok use distribute?
Yup! So what do you get?
a= 2b + 2c
a= 2 (b+c) a = 2b + 2c Good! So now what do we do to further get the C closer to being by itself?
Hint: There's a 2b and a 2 attached to the C. Is it easier to divide stuff? Or to subtract stuff?
divide
To be honest, I think subtraction's easier. BUT, it works both ways. So what are we left with after dividing by 2?
Whoops... gave away the number. But you were going to divide by 2 anyway, right?
so it cancels out right?
Well, the 2s cancel out. But don't forget: if you divide one side by two, you must do the same to the other. But, would you like to see an easier way?
yes
Okie dokie. When you were at this step: a = 2b + 2c It'd be easier to make the 2b go to the other side. How can we move it to there?
Hint: if you try dividing, you'd be left with a/2b = 2c/2b+1 So... you can tell you don't want to divide.
Still here roseanne? I can tell you what to do if it's confusing.
no I understand
How am I going to know that on my midterm
im just wanting to understand
Okie dokie. So what do we do with a = 2b + 2c to isolate the 2c further?
subtract
That's right :D Now that we have -2b + a = 2c, what is our final step?
Hint: It's easier if you view it with parentheses: (-2b + a) = 2c
So let's do that last step and go onto the other questions.
Still here roseanne? Just tell me what the final step is and we can get crackin' on the next few questions. These will be a lot easier since you'll know the steps.
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