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Mathematics 21 Online
OpenStudy (anonymous):

How would i Factor a polynomial completley when the equation is 5y(y+3)-2(y+3)

OpenStudy (anonymous):

5y(y+3) - 2(y+3) (5y^2 + 15y) - (2y +6) 15y^2 + 13y - 6

OpenStudy (anonymous):

and then... (5y+6) (3y-1)

OpenStudy (anonymous):

is that the last step?

OpenStudy (anonymous):

I believe so. Is that not what u were looking for?

OpenStudy (anonymous):

yes . thankyou

OpenStudy (anonymous):

np : ) good practice!

OpenStudy (anonymous):

couldnt you have just gotten (5y-2)(y+3) ...

OpenStudy (anonymous):

in fact, math morons answer is incorrect

OpenStudy (anonymous):

how so?

OpenStudy (anonymous):

apologies, Daniel. Arman is correct, I added a 1 where it was not suppose to be and messed up the subsequent equations. Let me take another look...

OpenStudy (anonymous):

5y(y+3) - 2(y+3) (5y^2 + 15y) - (2y +6) this, however simplifies to 5y^2 -13y -6 which can be factored to ...

OpenStudy (anonymous):

(5y+2)(y-3) I believe

OpenStudy (anonymous):

or actually, Arman's answer works too

OpenStudy (anonymous):

THANKYOU! ;)

OpenStudy (anonymous):

very welcome

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