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How would i Factor a polynomial completley when the equation is 5y(y+3)-2(y+3)
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5y(y+3) - 2(y+3) (5y^2 + 15y) - (2y +6) 15y^2 + 13y - 6
and then... (5y+6) (3y-1)
is that the last step?
I believe so. Is that not what u were looking for?
yes . thankyou
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np : ) good practice!
couldnt you have just gotten (5y-2)(y+3) ...
in fact, math morons answer is incorrect
how so?
apologies, Daniel. Arman is correct, I added a 1 where it was not suppose to be and messed up the subsequent equations. Let me take another look...
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5y(y+3) - 2(y+3) (5y^2 + 15y) - (2y +6) this, however simplifies to 5y^2 -13y -6 which can be factored to ...
(5y+2)(y-3) I believe
or actually, Arman's answer works too
THANKYOU! ;)
very welcome
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