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Write the inverse using the notation f^-1(x) f(x)=x+7/2
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Ok, the way I like to do inverses is to remember that \(f(f^{-1}(x)) = x\) So that means you take the original equation. And swap the x with \(f^{-1}(x)\) and the f(x) with x.
Then you solve it for \(f^{-1}(x)\)
f^-1(x)=2x-7 ?
\(x = f^{-1}(x) + \frac{7}{2}\)\[\implies f^{-1}(x) = x - \frac{7}{2}\]
Just subtract 7/2 from both sides.
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Does that make sense? Do you follow what I did there?
Yes, thanks!
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