Can somebody explain how my solutions manual got y=o for solving the following equation?
(3 - 5y)/ (2 + y) = (3 + 5y)/ (2 - y)
I've tried inserting 0 for y...and it's not coming out right for me.

Question

Can somebody explain how my solutions manual got y=o for solving the following equation? 
(3 - 5y)/ (2 + y) = (3 + 5y)/ (2 - y)
I've tried inserting 0 for y...and it's not coming out right for me.

anonymous · Answer

if you replace y by 0 both sides are 
$$\frac{3}{2}$$ yes.  so that shows the answer is correct even if it doesn't explain how to get it

anonymous · Answer

i would try "cross multiplying' to get 
$$(2-y)(3-5x)=(2+y)(3+5x)$$

anonymous · Answer

I'm trying to get it to equal 3/2 on each side..feel free to go elsewhere on the sight, while I try and get this to work..

anonymous · Answer

light bulb came on, thanks..

anonymous · Answer

i have no idea why i put those x's there.  let me write it correctly

anonymous · Answer

$$(2-y)(3-5y)=(2+y)(3+5y)$$

anonymous · Answer

multiply out and you will see that y = 0