Question

(y-1)/(y+1)= c((x-1)/(x+1))
how would you solve for y here?

Answer 1

(y - 1)(x + 1) = c(x - 1)(y + 1)

yx + y - x - 1 = cyx + cx - cy - c

y(x + 1) - x - 1 - cyx + cy = cx - c

y(x + 1 + c - cx) = x(c + 1) - c + 1

y(x(1 - c) + 1 + c) = x(c + 1) - c + 1

y = [x(c+1) - c + 1]/[x(1-c) + 1 + c]

Answer 2

y cannot be -1, nor can x.

the simplest case is when c = 1, in which case y = x

Answer 3

thanks, brother