Question

can you factorize it for me please (l+m)2 - (l-m)2

Answer 1

This is basically a^2-b^2 = (a-b)(a+b)
so:
(l+m)2 - (l-m)2 = [(l+m) + (l-m)][(l+m) - (l-m)]

Answer 2

or 2lm = (l+m)^2 - (l-m)^2

Answer 3

now just simplify..
[(l+m) + (l-m)][(l+m) - (l-m)] = [2l][2m] = 4lm

Answer 4

(l+m)2 - (l-m)2 = [(l+m) + (l-m)][(l+m) - (l-m)] = [2l] [2m] = 4 *l*m

Answer 5

\[a^2-b^2=(a+b)(a-b)\] use
\[a=l+m,b=l-m\]

Answer 6

4lm = (l+m)^2 - (l-m)^2

Answer 7

when you substitute you get
\[(l+m+l-m)(l+m-(l-m)\]
\[=(2l)(2m)=4lm\] just like everyone else said