Question

can you factor this?
32x^3-1372x^3y^3

Answer 1

The Wolfram factorization is an answer.

If you had to do this manually, you might be able to discover y = 2/7 but not easily, so I would just stop at

4x^3(8-343y^2) in that case.

Answer 2

\[=4x^3(8-343y^3)\]
\[=4x^3(2^3-(7y)^3)\]

then \(2^3-(7y)^3 can be factorised
identity(a^3-b^3)=(a-b) (a^2+a b+b^2)