I am new to the group and I am studying trig identities. I have a problem that asks me to express the sin function as an expression of cot. Can someone help?

Question

anonymous · Answer

More information: sin$$\sin \theta = \cos \theta \div \cot \theta$$

anonymous · Answer

wt do we hve to do in this prob?

anonymous · Answer

The problem is express Sin as a function of Cot

anonymous · Answer

that would be a miracle

anonymous · Answer

i suppose you could write 
$$\cot(x)=\pm\frac{\sqrt{1-\sin^2(x)}}{\sin(x)}$$

anonymous · Answer

oh worry you wanted sin in terms of cotangent and i gave it the other way

anonymous · Answer

Thanks for noting that! It was going to be my next question.

anonymous · Answer

der wuld b couple f more ways to write it.....wt say satellite73?

anonymous · Answer

good.  glad we got one done at least.

anonymous · Answer

strikes me as silly.  but what do i know?

anonymous · Answer

Trig identities are a little strange I agree, but it is still one of the key exercises. I guess I am still wondering about the steps in between. Thanks for trying.