Question

Calculus integral question...somehow I sense that satellite73 will get to this before anyone else does:

Answer 1

let's see

Answer 2

D = integral of velocity = Int ( 3t - 10 ) = int ( 3t^2/2 - 10t )

Answer 3

wait sorry
D = 3t^2/2 - 10t +C

Answer 4

Actually we got limits of integration so:
3t^2/2 - 10t from 0 to 4

Answer 5

3*16/2 - 40 = 3*8-40 = 24-40 = -16

Answer 6

first one is
\[\int_0^4 3-10tdt\]

Answer 7

3t - 10 satellite u're wrong

Answer 8

Integral, impressive. That is correct

Answer 9

lol now 2nd one:
We gotta check where it changed directions..

Answer 10

try just 16

Answer 11

cuz usually distance is abs(disp)

Answer 12

oops

Answer 13

would help if i could read wouldn't it?

Answer 14

i think so..

Answer 15

16's not right :/

Answer 16

yeah it is -16

Answer 17

aww i knew it wouldn't be that simple..

Answer 18

Nope it isnt -16 either

Answer 19

what?

Answer 20

No he is talking about part 2

Answer 21

Yeah i'm talking about part 2. Integral got the answer for part 1

Answer 22

oh part two you have to break it up into two pieces

Answer 23

oaky do this:
3t-10=0
3t=10
t = 10/3 and split the limits at 10/3

Answer 24

So it's from 0 to 10/3 and 10/3 to 4. Then evaluate individual integrals and add the abs values of those two numbers.

Answer 25

Satellite is what im doing right?

Answer 26

Yeah, is that the right way to do it, satellite? and do you have an answer Integral?

Answer 27

what integral said. you need
\[\int_0^{\frac{10}{3}}10-3t dt+\int_{\frac{10}{3}}^43t-10dt\]

Answer 28

yes what integral said.

Answer 29

abs(-50/3) + abs(2/3) = 50/3 + 2/3 = 52/3

Answer 30

yes. right

Answer 31

17.333

Answer 32

YAY!!! Time to do banana dance!

Answer 33

http://e.vampirefreaks.com/emotes/banana.gif

Answer 34

banana dance?

Answer 35

That is correct, well done guys