Question

Find the equation of a line which passes through point (1, 7) and is perpendicular to the line formed by the equation -2x + -10y = -9. Express it in slope-intercept form.

Answer 1

i already told you y=-5x+12

Answer 2

dont forgot medal

Answer 3

its not 12 its either 2 or -2

Answer 4

y=5x+2

Answer 5

The line that is given has a slope of -2/10
-10y=2x-9
y=(2/-10)x+9/10 You are interested only in the slope 2/-10 because a line that is perpendicular will have a slope that is a negative reciprocal of that slope or the slope of the perpendicular line will be 5 m=5.

since you have a point (given) and you have calculated the slope, you can now write the equation of the line that is perpendicular.
y-7
5= ------ cross multiply
x-1
5x-5 = y-7
y=5x -5-(-7)
y=5x + 2 (answer)