Question

PLs. help me simplifying this:
x^3+64y^3/(x^2-4xy+16y^2)(x^2-16y^2)

Answer 1

holy moly

Answer 2

my ans is.. \[1/x-4y\]

Answer 3

i know im wrong

Answer 4

numerator is the sum of two cubes so it factor as
\[x^3+64y^3=(x+4y)(x^2-4xy+16)\]

Answer 5

yah, i got that

Answer 6

one factor cancels. then cancel the
\[x+4y\] and you get
\[\frac{1}{x-4y}\]

Answer 7

ok looks like you got these no problem. factor and cancel gets it

Answer 8

you are not wrong. you are right. done

Answer 9

thank you again