Question

3^(2x) + 3^x - 2 =0

Answer 1

solve as a quadratic in \[3^x\]

Answer 2

like solving
\[z^2+3x-2=0\]
\[z=\frac{-3\pm\sqrt{17}}{2}\]
\[3^x=\frac{-3+\sqrt{17}}{2}\]

Answer 3

only used positive root because
\[3^x>0\]

Answer 4

then solve for x. if you want an actual number you have to use the change of base formula. if you want a math teacher answer then you can just say is it the log base 3 of that answer

Answer 5

cool. thanks

Answer 6

yw